(y^2-4)(4y^2-4y+5)=

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Solution for (y^2-4)(4y^2-4y+5)= equation: 


Simplifying
(y2 + -4)(4y2 + -4y + 5) = 0

Reorder the terms:
(-4 + y2)(4y2 + -4y + 5) = 0

Reorder the terms:
(-4 + y2)(5 + -4y + 4y2) = 0

Multiply (-4 + y2) * (5 + -4y + 4y2)
(-4(5 + -4y + 4y2) + y2(5 + -4y + 4y2)) = 0
((5 * -4 + -4y * -4 + 4y2 * -4) + y2(5 + -4y + 4y2)) = 0
((-20 + 16y + -16y2) + y2(5 + -4y + 4y2)) = 0
(-20 + 16y + -16y2 + (5 * y2 + -4y * y2 + 4y2 * y2)) = 0
(-20 + 16y + -16y2 + (5y2 + -4y3 + 4y4)) = 0

Combine like terms: -16y2 + 5y2 = -11y2
(-20 + 16y + -11y2 + -4y3 + 4y4) = 0

Solving
-20 + 16y + -11y2 + -4y3 + 4y4 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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